derivative of sin(7x+cos(2x))

Lösung

\frac{d}{d x} (sin (7 x) + cos (2 x))

cos (7 x) \cdot 7 - sin (2 x) \cdot 2

Schritte zur Lösung

\frac{d}{d x} (sin (7 x) + cos (2 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (7 x)) + \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (sin (7 x)) = cos (7 x) \cdot 7

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= cos (7 x) \cdot 7 - sin (2 x) \cdot 2

\frac{\partial}{\partial x} (\frac{e ^{v}}{u ( v , x ) + v ^{9}})

x \to - 1 lim (- x^{2} + 7 x - 8)

n = 1 \sum \infty 2 e^{- 8 n}

d er i v a t i v e - \frac{6}{x ^{2}}

\frac{d}{d x} (x^{5} ln (8 x))