derivative y=(2x+1)+2/((2x+1)^3)

Lösung

ableitung von

y = (2 x + 1) + \frac{2}{( 2 x + 1 ) ^{3}}

- \frac{12}{( 2 x + 1 ) ^{4}} + 2

Schritte zur Lösung

\frac{d}{d x} ((2 x + 1) + \frac{2}{( 2 x + 1 ) ^{3}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (1) + \frac{d}{d x} (\frac{2}{( 2 x + 1 ) ^{3}})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{2}{( 2 x + 1 ) ^{3}}) = - \frac{12}{( 2 x + 1 ) ^{4}}

= 2 + 0 - \frac{12}{( 2 x + 1 ) ^{4}}

Vereinfache

= - \frac{12}{( 2 x + 1 ) ^{4}} + 2

\int_{- 1}^{1} x (1 - x)^{2} d x

x \to 0 + lim (\frac{1}{sin ^{2} ( x )})

\frac{d}{d x} (\frac{24 x ( x ^{2} + 1 )}{( 1 - x ^{2} ) ^{4}})

\int \frac{x ^{2} ln ( x )}{2} d x

n = 0 \sum \infty \frac{n ^{2}}{e ^{n}}