-2x^2y^{''}+3xy^'-y=0

Lösung

- 2 x^{2} y^{^{''}} + 3 x y^{^{'}} - y = 0

y = c_{1} x^{\frac{5 - 17}{4}} + c_{2} x^{\frac{5 + 17}{4}}

Schritte zur Lösung

- 2 x^{2} y^{''} (x) + 3 x y^{'} (x) - y = 0

Solve linear ODE:

y = c_{1} x^{\frac{5 - 17}{4}} + c_{2} x^{\frac{5 + 17}{4}}

y = c_{1} x^{\frac{5 - 17}{4}} + c_{2} x^{\frac{5 + 17}{4}}

\int \frac{x ^{4}}{x ^{2} + 3} d x

\frac{d}{d x} ((x + c) e^{- x})

d er i v a t i v e f (x) = \frac{( 3 x ^{2} - x + 1 )}{x}

d er i v a t i v e 6 x^{5} (x - 4)^{5} + 5 (x - 4)^{4} x^{6}

\frac{\partial}{\partial x} (\frac{- c x}{x ^{2} + y ^{2}})