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Beliebt Rechnen >

(9x^2+y-1)-(4y-x)y^'=0

Lösung

(9 x^{2} + y - 1) - (4 y - x) y^{^{'}} = 0

Lösung

y = - \frac{- x + x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}, y = - \frac{- x - x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}

Schritte zur Lösung

(9 x^{2} + y - 1) - (4 y - x) y^{'} (x) = 0

Solve exact ODE:

y = - \frac{- x + x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}, y = - \frac{- x - x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}

y = - \frac{- x + x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}, y = - \frac{- x - x ^{2} + 8 ( 3 x ^{3} - x - c _{1} )}{4}

Graph

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