What is the derivative of x^2-4x+4 ?

The derivative of x^2-4x+4 is 2x-4

What is the first derivative of x^2-4x+4 ?

The first derivative of x^2-4x+4 is 2x-4

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\frac{d}{d x} (x^{2} - 4 x + 4)

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (4) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

\frac{d}{d x} (\frac{3}{x ^{5}})

x \to 2 lim ((x - 2)^{4} (5 x^{2}))

d er i v a t i v e \frac{e ^{x}}{x ^{3} + 1}

\int \frac{1}{x ( x - 2 ) ^{2}} d x

\int_{0}^{\infty} \frac{1}{x ^{2} - 1} d x

What is the derivative of x^2-4x+4 ?
The derivative of x^2-4x+4 is 2x-4
What is the first derivative of x^2-4x+4 ?
The first derivative of x^2-4x+4 is 2x-4