What is the solution for y^{''}-10y^'+9y=27 ?

The solution for y^{''}-10y^'+9y=27 is y=c_{1}e^{9t}+c_{2}e^t+3

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y^{''}-10y^'+9y=27

y^{^{''}} - 10 y^{^{'}} + 9 y = 27

y = c_{1} e^{9 t} + c_{2} e^{t} + 3

Solution steps

y^{''} (t) - 10 y^{'} (t) + 9 y = 27

Solve linear ODE:

y = c_{1} e^{9 t} + c_{2} e^{t} + 3

y = c_{1} e^{9 t} + c_{2} e^{t} + 3

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\frac{d}{d x} (\frac{3}{x ^{5}})

x \to 2 lim ((x - 2)^{4} (5 x^{2}))

d er i v a t i v e \frac{e ^{x}}{x ^{3} + 1}

\int \frac{1}{x ( x - 2 ) ^{2}} d x

What is the solution for y^{''}-10y^'+9y=27 ?
The solution for y^{''}-10y^'+9y=27 is y=c_{1}e^{9t}+c_{2}e^t+3