What is the derivative of f(x)=3x^2+12 ?

The derivative of f(x)=3x^2+12 is 6x

What is the first derivative of f(x)=3x^2+12 ?

The first derivative of f(x)=3x^2+12 is 6x

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derivative of

f (x) = 3 x^{2} + 12

6 x

Solution steps

\frac{d}{d x} (3 x^{2} + 12)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (12)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (12) = 0

= 6 x + 0

Simplify

= 6 x

\frac{d}{d x} (\frac{1}{x + \frac{1}{x + 1}})

\frac{\partial}{\partial x} (ln (sin (x y)))

l a pl a ce t r an s f or m sin^{2} (4 t)

\frac{\partial}{\partial x} (2 \frac{y}{x})

x \to 0 lim (e^{4 x})

What is the derivative of f(x)=3x^2+12 ?
The derivative of f(x)=3x^2+12 is 6x
What is the first derivative of f(x)=3x^2+12 ?
The first derivative of f(x)=3x^2+12 is 6x