integral from 0 to 1 of 1/(sqrt(x+2))

Lösung

\int_{0}^{1} \frac{1}{x + 2} d x

23 - 22

Dezimale

0.63567 \dots

Schritte zur Lösung

\int_{0}^{1} \frac{1}{x + 2} d x

Wende U-Substitution an

= \int_{2}^{3} 2 d u

Integral einer Konstanten :

\int a d x = a x

= [2 u]_{2}^{3}

Berechne die Grenzen:

23 - 22

= 23 - 22

in v erse l a pl a ce \frac{7 s + 4}{2 s ^{2} + 16 s + 30}

d er i v a t i v e \frac{x - 2}{x ^{2} - 4}

x \to 2 lim (- x + 2 x^{2} - 1)

in v erse l a pl a ce \frac{10}{s ^{2} + 2 s + 10}

\frac{\partial}{\partial x} (4 x^{8} y^{6} + 6 x^{7} y^{5})