(1+cos(x))y^'=(1+e^{-y})sin(x)

Lösung

(1 + cos (x)) y^{^{'}} = (1 + e^{- y}) sin (x)

y = ln (\frac{c _{1}}{1 + cos ( x )} - 1)

Schritte zur Lösung

(1 + cos (x)) y^{'} (x) = (1 + e^{- y}) sin (x)

Solve separable ODE:

y = ln (\frac{c _{1}}{1 + cos ( x )} - 1)

y = ln (\frac{c _{1}}{1 + cos ( x )} - 1)

\int \frac{1}{( 2 x - 1 ) ^{2}} d x

\frac{\partial}{\partial x} (arctan (x^{2} y))

\int_{- \infty}^{- 1} 0 d x

\int \frac{18 x - 6}{3 x ^{2} - 2 x - 7} d x

in v erse l a pl a ce \frac{10}{5 s + 1}