面积 y=sqrt(1-x^2),y=x^2-1

解答

面积

y = 1 - x^{2}, y = x^{2} - 1

\frac{π}{2} + \frac{4}{3}

十进制

2.90412 \dots

求解步骤

使用面积公式:

\int_{- 1}^{1} 1 - x^{2} - (x^{2} - 1) d x

解

\int_{- 1}^{1} 1 - x^{2} - (x^{2} - 1) d x : \frac{π}{2} + \frac{4}{3}

面积为:

= \frac{π}{2} + \frac{4}{3}

x^{3} y y^{^{'}} + x^{2} y^{2} = y^{5}

\frac{\partial}{\partial y} (x^{2} e^{- \frac{x}{y}})

\int 13 e^{u} d u

t an g e n t f (x) = x^{2} - 3 x + 5, at x = 2

y^{^{'}} = \frac{y}{x} + 1 + (\frac{y}{x})^{2}