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Beliebt Rechnen >

inverselaplace 1/(s^2)-1/s+1/(s-2)

Lösung

inverse laplace transformation

\frac{1}{s ^{2}} - \frac{1}{s} + \frac{1}{s - 2}

Lösung

t - H (t) + e^{2 t}

Schritte zur Lösung

L^{- 1} {\frac{1}{s ^{2}} - \frac{1}{s} + \frac{1}{s - 2}}

Wende die lineare Eigenschaftder inversen Laplace-Transformation an:

Für Funktionen

f (s), g (s)

und Konstanten

a, b : L^{- 1} {a \cdot f (s) + b \cdot g (s)} = a \cdot L^{- 1} {f (s)} + b \cdot L^{- 1} {g (s)}

= L^{- 1} {\frac{1}{s ^{2}}} - L^{- 1} {\frac{1}{s}} + L^{- 1} {\frac{1}{s - 2}}

L^{- 1} {\frac{1}{s ^{2}}} : t

L^{- 1} {\frac{1}{s}} : H (t)

L^{- 1} {\frac{1}{s - 2}} : e^{2 t}

= t - H (t) + e^{2 t}

Beliebte Beispiele

tangent f(x)=(1-x)(x^2-3)^2

t an g e n t f (x) = (1 - x) (x^{2} - 3)^{2}

sum from n=0 to infinity of 1^{2n}

n = 0 \sum \infty 1^{2 n}

(\partial)/(\partial z)(xcos(z))

\frac{\partial}{\partial z} (x cos (z))

(dy)/(dx)=y(1/x-y)

\frac{d y}{d x} = y (\frac{1}{x} - y)

(\partial)/(\partial x)(3y-7)

\frac{\partial}{\partial x} (3 y - 7)