What is area y=x,y=(x-1)^2 ?

The answer to area y=x,y=(x-1)^2 is -sqrt(5)+(11sqrt(5))/6

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area y=x,y=(x-1)^2

area

y = x, y = (x - 1)^{2}

- 5 + \frac{11 5}{6}

Decimal

1.86338 \dots

Solution steps

Apply the area formula:

\int_{\frac{3 - 5}{2}}^{\frac{3 + 5}{2}} x - (x - 1)^{2} d x

Solve

\int_{\frac{3 - 5}{2}}^{\frac{3 + 5}{2}} x - (x - 1)^{2} d x : - 5 + \frac{11 5}{6}

The area is:

= - 5 + \frac{11 5}{6}

\int \frac{( 9 + x + x )}{x} d x

\int sec^{2} (2 x) sin (2 x) d x

x \to - \infty lim (g (x))

\int 6 x - 7 d x

16 y^{^{''}} + 3 y = 0

What is area y=x,y=(x-1)^2 ?
The answer to area y=x,y=(x-1)^2 is -sqrt(5)+(11sqrt(5))/6