derivative sqrt((x^2-1)/(x^2+1))

Lösung

ableitung von

\frac{x ^{2} - 1}{x ^{2} + 1}

\frac{2 x}{x ^{2} - 1 ( x ^{2} + 1 ) ^{\frac{3}{2}}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} + 1})

Wende die Kettenregel an:

\frac{1}{2 \frac{x ^{2} - 1}{x ^{2} + 1}} \frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} + 1})

= \frac{1}{2 \frac{x ^{2} - 1}{x ^{2} + 1}} \frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} + 1})

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} + 1}) = \frac{4 x}{( x ^{2} + 1 ) ^{2}}

= \frac{1}{2 \frac{x ^{2} - 1}{x ^{2} + 1}} \cdot \frac{4 x}{( x ^{2} + 1 ) ^{2}}

Vereinfache

\frac{1}{2 \frac{x ^{2} - 1}{x ^{2} + 1}} \cdot \frac{4 x}{( x ^{2} + 1 ) ^{2}} : \frac{2 x}{x ^{2} - 1 ( x ^{2} + 1 ) ^{\frac{3}{2}}}

= \frac{2 x}{x ^{2} - 1 ( x ^{2} + 1 ) ^{\frac{3}{2}}}

n = 2 \sum \infty ln (\frac{1}{n})

in v erse l a pl a ce \frac{1}{2 x ^{2} + x + 1}

\frac{d N}{d t} = 5 - N, N (2) = 2

\int (\frac{e ^{x} - e ^{- x}}{2}) d x

\int \frac{\frac{1}{e ^{x} + e ^{2 x}}}{- e ^{- 3 x}} d x