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Popular Calculus >

y^'=t-ty

Solution

y^{^{'}} = t - t y

Solution

y = e^{- \frac{t ^{2}}{2} + c_{1}} + 1

Solution steps

y^{'} (t) = t - t y

Solve separable ODE:

y = e^{- \frac{t ^{2}}{2} + c_{1}} + 1

y = e^{- \frac{t ^{2}}{2} + c_{1}} + 1

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=t-ty ?
The solution for y^'=t-ty is y=e^{-(t^2)/2+c_{1}}+1