What is the derivative of (sqrt(3x^2)/2) ?

The derivative of (sqrt(3x^2)/2) is (sqrt(3))/2

What is the first derivative of (sqrt(3x^2)/2) ?

The first derivative of (sqrt(3x^2)/2) is (sqrt(3))/2

\frac{d}{d x} (\frac{3 x ^{2}}{2})

\frac{3}{2}

Decimal

0.86602 \dots

Solution steps

\frac{d}{d x} (\frac{3 x ^{2}}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (3 x^{2})

Apply the chain rule:

\frac{1}{2 3 x ^{2}} \frac{d}{d x} (3 x^{2})

= \frac{1}{2 3 x ^{2}} \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (3 x^{2}) = 6 x

= \frac{1}{2} \cdot \frac{1}{2 3 x ^{2}} \cdot 6 x

Simplify

\frac{1}{2} \cdot \frac{1}{2 3 x ^{2}} \cdot 6 x : \frac{3}{2}

= \frac{3}{2}

\frac{d}{d x} (5 ln (12 x))

\frac{d y}{d x} - 2 y = x

\frac{d}{d x} (6 x + 7)

\int (\frac{1 + t}{t})^{3} d t

\int x \cdot ab \cdot e^{- ab x + ab c} d x

What is the derivative of (sqrt(3x^2)/2) ?
The derivative of (sqrt(3x^2)/2) is (sqrt(3))/2
What is the first derivative of (sqrt(3x^2)/2) ?
The first derivative of (sqrt(3x^2)/2) is (sqrt(3))/2