What is the first derivative of (3x/x) ?

The first derivative of (3x/x) is 0

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derivative of (3x/x)

\frac{d}{d x} (\frac{3 x}{x})

0

Solution steps

\frac{d}{d x} (\frac{3 x}{x})

\frac{3 x}{x} = 3

= \frac{d}{d x} (3)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

t an g e n t f (x) = (2)^{x}, at x = 6

y^{^{''}} + 14 y^{^{'}} + 28 y = 6675 e^{2 t} cos (15 t)

l a pl a ce t r an s f or m t^{2} sin (t)

d er i v a t i v e \frac{1 + 5 t}{ln ( t ^{2} )}

\int \frac{x ^{2}}{x ^{6} - 1} d x