What is the first derivative of ln(e^x) ?

The first derivative of ln(e^x) is 1

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derivative of ln(e^x)

derivative of

ln (e^{x})

1

Solution steps

\frac{d}{d x} (ln (e^{x}))

Simplify

ln (e^{x}) : x

= \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 1

\frac{d}{d x} (3 e^{x} + \frac{8}{3 x})

\int_{0}^{1} π (x)^{2} d x

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{3 x} (1 + x)

\int_{0}^{3} 4 x d x

(2 x + y) d x + (x - 2 y) d y = 0