What is the derivative of 3e^x+8/(\sqrt[3]{x}) ?

The derivative of 3e^x+8/(\sqrt[3]{x}) is 3e^x-8/(3x^{4/3)}

What is the first derivative of 3e^x+8/(\sqrt[3]{x}) ?

The first derivative of 3e^x+8/(\sqrt[3]{x}) is 3e^x-8/(3x^{4/3)}

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\frac{d}{d x} (3 e^{x} + \frac{8}{3 x})

3 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (3 e^{x} + \frac{8}{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 e^{x}) + \frac{d}{d x} (\frac{8}{3 x})

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

\frac{d}{d x} (\frac{8}{3 x}) = - \frac{8}{3 x ^{\frac{4}{3}}}

= 3 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

\int_{0}^{1} π (x)^{2} d x

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{3 x} (1 + x)

\int_{0}^{3} 4 x d x

(2 x + y) d x + (x - 2 y) d y = 0

f (x) = 4 x^{2} ln (4 x)

What is the derivative of 3e^x+8/(\sqrt[3]{x}) ?
The derivative of 3e^x+8/(\sqrt[3]{x}) is 3e^x-8/(3x^{4/3)}
What is the first derivative of 3e^x+8/(\sqrt[3]{x}) ?
The first derivative of 3e^x+8/(\sqrt[3]{x}) is 3e^x-8/(3x^{4/3)}