integral from 2 to 3 of (x^2-4)

Lösung

\int_{2}^{3} (x^{2} - 4) d x

\frac{7}{3}

Dezimale

2.33333 \dots

Schritte zur Lösung

\int_{2}^{3} x^{2} - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{3} x^{2} d x - \int_{2}^{3} 4 d x

\int_{2}^{3} x^{2} d x = \frac{19}{3}

\int_{2}^{3} 4 d x = 4

= \frac{19}{3} - 4

Vereinfache

\frac{19}{3} - 4 : \frac{7}{3}

= \frac{7}{3}

t an g e n t f (x) = \frac{6 x}{2 + x ^{2}}, (2, 2)

\int (3 x + 2) d x

d er i v a t i v e y = 19 cos (\frac{x}{b} - 2.5) + 19

\frac{\partial}{\partial x} (sin^{2} (2 x + 3 y))

\int_{0}^{1} x^{2} (x^{3} - 2)^{3} d x