limit as x approaches+1+of 2/x-1/(ln(x))

解答

x \to + 1 + lim (\frac{2}{x} - \frac{1}{ln ( x )})

- \infty

求解步骤

x \to 1 + lim (\frac{2}{x} - \frac{1}{ln ( x )})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

不定型除外

= x \to 1 + lim (\frac{2}{x}) - x \to 1 + lim (\frac{1}{ln ( x )})

x \to 1 + lim (\frac{2}{x}) = 2

x \to 1 + lim (\frac{1}{ln ( x )}) = \infty

= 2 - \infty

运用无穷大属性:

c - \infty = - \infty

= - \infty

\frac{\partial}{\partial x} (x^{2} - y^{2} + z^{2} - 2 z - 4)

\int - 17 sin^{4} (x) cos (x) d x

d er i v a t i v e 5 x^{\frac{1}{3}} - 5 x^{- \frac{2}{3}}

d er i v a t i v e (x^{2} + 1)^{x}

in v erse l a pl a ce \frac{16}{s ( s ^{2} + 4 s + 16 )}