(ln(1+x))^'

Lösung

(ln (1 + x))^{^{'}}

\frac{1}{1 + x}

Schritte zur Lösung

(ln (1 + x))^{'}

Wende die Kettenregel an:

\frac{1}{1 + x} (1 + x)^{'}

= \frac{1}{1 + x} (1 + x)^{'}

(1 + x)^{'} = 1

= \frac{1}{1 + x} \cdot 1

Vereinfache

= \frac{1}{1 + x}

\int cos (x) + sec (x) tan (x) d x

\int \frac{2 e ^{x} + 4}{2 e ^{x} - 4} d x

\int \frac{1}{ln ( n )}

x \to + 1 + lim (\frac{2}{x} - \frac{1}{ln ( x )})

\frac{\partial}{\partial x} (x^{2} - y^{2} + z^{2} - 2 z - 4)