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Beliebt Rechnen >

sum from n=2 to infinity of (3/4)^n

Lösung

n = 2 \sum \infty (\frac{3}{4})^{n}

Lösung

\frac{9}{4}

+1

Dezimale

2.25

Schritte zur Lösung

n = 2 \sum \infty (\frac{3}{4})^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty (\frac{3}{4})^{n} - (\frac{3}{4})^{0} - (\frac{3}{4})^{1}

n = 0 \sum \infty (\frac{3}{4})^{n} = 4

= 4 - (\frac{3}{4})^{0} - (\frac{3}{4})^{1}

Vereinfache

4 - (\frac{3}{4})^{0} - (\frac{3}{4})^{1} : \frac{9}{4}

= \frac{9}{4}

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