faktorisieren w^6-64

Lösung

faktorisieren

w^{6} - 64

(w + 2) (w - 2) (w^{2} + 2 w + 4) (w^{2} - 2 w + 4)

Schritte zur Lösung

w^{6} - 64

Wende Exponentenregel an

= (w^{2})^{3} - 4^{3}

Wende Formel zur Differenz von dritten Potenzen an:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(w^{2})^{3} - 4^{3} = (w^{2} - 4) (w^{4} + 4 w^{2} + 4^{2})

= (w^{2} - 4) (w^{4} + 4 w^{2} + 4^{2})

Faktorisiere

w^{2} - 4 : (w + 2) (w - 2)

= (w + 2) (w - 2) (w^{4} + 4 w^{2} + 4^{2})

Faktorisiere

w^{4} + 4 w^{2} + 4^{2} : (w^{2} + 4 + 2 w) (w^{2} + 4 - 2 w)

= (w + 2) (w - 2) (w^{2} + 4 + 2 w) (w^{2} + 4 - 2 w)

= (w + 2) (w - 2) (w^{2} + 2 w + 4) (w^{2} - 2 w + 4)

\frac{4 x + 1}{2} = \frac{8 x + 3}{3}

∣ 2 x + 7 ∣ \geq 5

d o main f (a) = \frac{4 a ^{2} - 36}{24 - 8 a}

s im pl i f y (\frac{5}{2})^{2} + 1

- 18 = - 6 y