-y^2-13y=0

解

- y^{2} - 13 y = 0

y = - 13, y = 0

解答ステップ

- y^{2} - 13 y = 0

解くとthe二次式

y_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 13)^{2} - 4 (- 1) \cdot 0 = 13

y_{1, 2} = \frac{- ( - 13 ) \pm 13}{2 ( - 1 )}

解を分離する

y_{1} = \frac{- ( - 13 ) + 13}{2 ( - 1 )}, y_{2} = \frac{- ( - 13 ) - 13}{2 ( - 1 )}

y = \frac{- ( - 13 ) + 13}{2 ( - 1 )} : - 13

y = \frac{- ( - 13 ) - 13}{2 ( - 1 )} : 0

二次equationの解:

y = - 13, y = 0