化简 (s^{2/5}t^{1/3})(s^{1/2}t^{1/2})

解答

化简

(s^{\frac{2}{5}} t^{\frac{1}{3}}) (s^{\frac{1}{2}} t^{\frac{1}{2}})

s^{\frac{9}{10}} t^{\frac{5}{6}}

求解步骤

(s^{\frac{2}{5}} t^{\frac{1}{3}}) (s^{\frac{1}{2}} t^{\frac{1}{2}})

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

s^{\frac{2}{5}} s^{\frac{1}{2}} = s^{\frac{2}{5} + \frac{1}{2}}

= t^{\frac{1}{3}} s^{\frac{2}{5} + \frac{1}{2}} t^{\frac{1}{2}}

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

t^{\frac{1}{3}} t^{\frac{1}{2}} = t^{\frac{1}{3} + \frac{1}{2}}

= s^{\frac{2}{5} + \frac{1}{2}} t^{\frac{1}{3} + \frac{1}{2}}

s^{\frac{2}{5} + \frac{1}{2}} = s^{\frac{9}{10}}

= s^{\frac{9}{10}} t^{\frac{1}{3} + \frac{1}{2}}

t^{\frac{1}{3} + \frac{1}{2}} = t^{\frac{5}{6}}

= s^{\frac{9}{10}} t^{\frac{5}{6}}

s im pl i f y \frac{2}{- 1 - 2}

3 (2 X - 3) + 2 (2 X - 2) + 10 = 5 X + 17

4 x + 5 > 49

s im pl i f y 6 (- \frac{3}{2})

\frac{x - 6}{x + 5} \geq \frac{x + 7}{x + 3}