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受欢迎的代数 >

390=-4.9t^2+60t+380

解答

390 = - 4.9 t^{2} + 60 t + 380

解答

t = \frac{10 ( 30 - 851 )}{49}, t = \frac{10 ( 30 + 851 )}{49}

+1

十进制

t = 0.16899 \dots, t = 12.07589 \dots

求解步骤

390 = - 4.9 t^{2} + 60 t + 380

在两边乘以

10

3900 = - 49 t^{2} + 600 t + 3800

交换两边

- 49 t^{2} + 600 t + 3800 = 3900

将

3900

para o lado esquerdo

- 49 t^{2} + 600 t - 100 = 0

使用求根公式求解

t_{1, 2} = \frac{- 600 \pm 60 0 ^{2} - 4 ( - 49 ) ( - 100 )}{2 ( - 49 )}

60 0^{2} - 4 (- 49) (- 100) = 20851

t_{1, 2} = \frac{- 600 \pm 20 851}{2 ( - 49 )}

将解分隔开

t_{1} = \frac{- 600 + 20 851}{2 ( - 49 )}, t_{2} = \frac{- 600 - 20 851}{2 ( - 49 )}

t = \frac{- 600 + 20 851}{2 ( - 49 )} : \frac{10 ( 30 - 851 )}{49}

t = \frac{- 600 - 20 851}{2 ( - 49 )} : \frac{10 ( 30 + 851 )}{49}

二次方程组的解是:

t = \frac{10 ( 30 - 851 )}{49}, t = \frac{10 ( 30 + 851 )}{49}

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