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受欢迎的代数 >

1=b^2+((3b)/2)^2

解答

1 = b^{2} + (\frac{3 b}{2})^{2}

解答

b = \frac{2}{13}, b = - \frac{2}{13}

+1

十进制

b = 0.55470 \dots, b = - 0.55470 \dots

求解步骤

1 = b^{2} + (\frac{3 b}{2})^{2}

展开

b^{2} + (\frac{3 b}{2})^{2} : \frac{13 b ^{2}}{4}

1 = \frac{13 b ^{2}}{4}

交换两边

\frac{13 b ^{2}}{4} = 1

将

1

para o lado esquerdo

\frac{13 b ^{2}}{4} - 1 = 0

使用求根公式求解

b_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot \frac{13}{4} ( - 1 )}{2 \cdot \frac{13}{4}}

0^{2} - 4 \cdot \frac{13}{4} (- 1) = 13

b_{1, 2} = \frac{- 0 \pm 13}{2 \cdot \frac{13}{4}}

将解分隔开

b_{1} = \frac{- 0 + 13}{2 \cdot \frac{13}{4}}, b_{2} = \frac{- 0 - 13}{2 \cdot \frac{13}{4}}

b = \frac{- 0 + 13}{2 \frac{13}{4}} : \frac{2}{13}

b = \frac{- 0 - 13}{2 \frac{13}{4}} : - \frac{2}{13}

二次方程组的解是:

b = \frac{2}{13}, b = - \frac{2}{13}

作图

流行的例子

∣ 1 x + 19 ∣ < 6

\frac{1}{x} \geq \frac{1}{x + 7}

化简 (-3-3i)^2

s im pl i f y (- 3 - 3 i)^{2}

∣ 2 - 4 t ∣ + 6 = 16

longmult 0.6*0.4

l o n g m u lt 0.6 \cdot 0.4