vereinfachen (81x^{-12}y^{32})^{3/4}

Lösung

vereinfachen

(81 x^{- 12} y^{32})^{\frac{3}{4}}

\frac{27 y ^{24}}{x ^{9}}

Schritte zur Lösung

(81 x^{- 12} y^{32})^{\frac{3}{4}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(81 x^{- 12} y^{32})^{\frac{3}{4}} = 8 1^{\frac{3}{4}} (x^{- 12})^{\frac{3}{4}} (y^{32})^{\frac{3}{4}}

= 8 1^{\frac{3}{4}} (x^{- 12})^{\frac{3}{4}} (y^{32})^{\frac{3}{4}}

8 1^{\frac{3}{4}} = 27

= 27 (x^{- 12})^{\frac{3}{4}} (y^{32})^{\frac{3}{4}}

Vereinfache

(x^{- 12})^{\frac{3}{4}} : \frac{1}{x ^{9}}

= 27 \cdot \frac{1}{x ^{9}} (y^{32})^{\frac{3}{4}}

Vereinfache

(y^{32})^{\frac{3}{4}} : y^{24}

= 27 \cdot \frac{1}{x ^{9}} y^{24}

Vereinfache

27 \cdot \frac{1}{x ^{9}} y^{24} : \frac{27 y ^{24}}{x ^{9}}

= \frac{27 y ^{24}}{x ^{9}}

4 x + 9 \geq - 11

∣ 4 a - 4 ∣ + 2 = 6

- 12 x \leq 72

s im pl i f y (- 7)^{2}

4 (x + 15) = 7 x