0=x^2-16x+64

解答

0 = x^{2} - 16 x + 64

x = 8

求解步骤

0 = x^{2} - 16 x + 64

交换两边

x^{2} - 16 x + 64 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 64 = 0

x_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 16 )}{2 \cdot 1}

\frac{- ( - 16 )}{2 \cdot 1} = 8

x = 8

二次方程组的解是:

x = 8

f a c t or t^{2} + t + \frac{1}{4}

s im pl i f y \frac{19 m + 3 m ^{3}}{14 m - 3} - \frac{12 m ^{2} + 3 m}{14 m - 3}

f a c t or 49 a^{2} - 14 a + 1

∣ x - 2 ∣ - 5 \leq - 2

s im pl i f y (\frac{1}{27})^{- \frac{2}{3}}