sqrt((2-x)^2)<= 3

解答

(2 - x)^{2} \leq 3

- 1 \leq x \leq 5

间隔符号

[- 1, 5]

求解步骤

(2 - x)^{2} \leq 3

两边进行平方

((2 - x)^{2})^{2} \leq 3^{2}

化简

4 - 4 x + x^{2} \leq 9

4 - 4 x + x^{2} \leq 9 : - 1 \leq x \leq 5

- 1 \leq x \leq 5

x^{2} + 12 x = 28

s im pl i f y 6 x^{5}

10 x^{2} - 11 x + 3 = 0

\frac{5 x}{x + 3} - \frac{6}{x + 3} > 10

f a c t or x y + 1 + x + y