(x+1)/(x-1)>= 2

Lösung

\frac{x + 1}{x - 1} \geq 2

1 < x \leq 3

Intervall-Notation

(1, 3]

Schritte zur Lösung

\frac{x + 1}{x - 1} \geq 2

Rewrite in standard form

\frac{- x + 3}{x - 1} \geq 0

Identifiziere die Intervalle

1 < x \leq 3

46 - 8 z = 14

2 (4 - 2 r) = - 2 (r + 5)

3 x - 1 = 2

6 x - 27 = - x^{2}

t + 25 = 26