化简 (2n^3-3n+5)/(n^3-2n^2+2)-2

解答

化简

\frac{2 n ^{3} - 3 n + 5}{n ^{3} - 2 n ^{2} + 2} - 2

\frac{4 n ^{2} - 3 n + 1}{n ^{3} - 2 n ^{2} + 2}

求解步骤

\frac{2 n ^{3} - 3 n + 5}{n ^{3} - 2 n ^{2} + 2} - 2

使用分式法则:

a + \frac{b}{c} = \frac{a c + b}{c}

= \frac{- 2 ( n ^{3} - 2 n ^{2} + 2 ) + 2 n ^{3} - 3 n + 5}{n ^{3} - 2 n ^{2} + 2}

化简

- 2 (n^{3} - 2 n^{2} + 2) + 2 n^{3} - 3 n + 5 : 4 n^{2} - 3 n + 1

= \frac{4 n ^{2} - 3 n + 1}{n ^{3} - 2 n ^{2} + 2}

\frac{x - 1}{8} \geq \frac{x - 3}{12} + \frac{1}{24}

2.2 > 2 - 0.4 x

3 x + 2 > 8

16 z^{2} - 56 z + 49 = 25

s im pl i f y \frac{45}{4}