p^2+6p+8=0

解

p^{2} + 6 p + 8 = 0

p = - 2, p = - 4

解答ステップ

p^{2} + 6 p + 8 = 0

解くとthe二次式

p_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

p_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

解を分離する

p_{1} = \frac{- 6 + 2}{2 \cdot 1}, p_{2} = \frac{- 6 - 2}{2 \cdot 1}

p = \frac{- 6 + 2}{2 \cdot 1} : - 2

p = \frac{- 6 - 2}{2 \cdot 1} : - 4

二次equationの解:

p = - 2, p = - 4