化简 (2i-1)^2

解答

化简

(2 i - 1)^{2}

- 3 - 4 i

求解步骤

(2 i - 1)^{2}

使用完全平方公式:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(2 i - 1)^{2} = (2 i)^{2} - 2 \cdot 2 i 1 + 1^{2}

= (2 i)^{2} - 2 \cdot 2 i 1 + 1^{2}

化简

(2 i)^{2} - 2 \cdot 2 i 1 + 1^{2} : - 4 i - 3

= - 4 i - 3

Rewrite in standard complex form:

- 3 - 4 i

= - 3 - 4 i

1.2 x = (3 - x) \cdot (3 - x)

∣ 2 x - 7 ∣ = ∣ x + 3 ∣

4 (x + 9) = 40

f a c t or 10 x^{2} + 3 x - 4

f a c t or 4 c^{4} + 6 c^{6} + 8 c