What are the solutions to the equation 3n^2=19 ?

The solutions to the equation 3n^2=19 are n=sqrt(19/3),n=-sqrt(19/3)

Find the zeros of 3n^2=19

The zeros of 3n^2=19 are n=sqrt(19/3),n=-sqrt(19/3)

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3 n^{2} = 19

n = \frac{19}{3}, n = - \frac{19}{3}

Decimal Notation

n = 2.51661 \dots, n = - 2.51661 \dots

Solution steps

3 n^{2} = 19

Divide both sides by

3

n^{2} = \frac{19}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{19}{3}, n = - \frac{19}{3}

\frac{π}{6} + \frac{π}{2}

23

∣ 2 x - 5 ∣ < 17

(\frac{4 c ^{- 5}}{8 d ^{0}})^{3}

What are the solutions to the equation 3n^2=19 ?
The solutions to the equation 3n^2=19 are n=sqrt(19/3),n=-sqrt(19/3)
Find the zeros of 3n^2=19
The zeros of 3n^2=19 are n=sqrt(19/3),n=-sqrt(19/3)