What are the solutions to the equation x^2+7x+4=0 ?

The solutions to the equation x^2+7x+4=0 are x=(-7+sqrt(33))/2 ,x=(-7-sqrt(33))/2

Find the zeros of x^2+7x+4=0

The zeros of x^2+7x+4=0 are x=(-7+sqrt(33))/2 ,x=(-7-sqrt(33))/2

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x^{2} + 7 x + 4 = 0

x = \frac{- 7 + 33}{2}, x = \frac{- 7 - 33}{2}

Decimal Notation

x = - 0.62771 \dots, x = - 6.37228 \dots

Solution steps

x^{2} + 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 4 = 33

x_{1, 2} = \frac{- 7 \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 33}{2 \cdot 1}, x_{2} = \frac{- 7 - 33}{2 \cdot 1}

x = \frac{- 7 + 33}{2 \cdot 1} : \frac{- 7 + 33}{2}

x = \frac{- 7 - 33}{2 \cdot 1} : \frac{- 7 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 33}{2}, x = \frac{- 7 - 33}{2}

∣ 4 (x - 1) + 2 ∣ \leq 18

\frac{7}{3} + \frac{1}{3}

2.2 h + 0.4 \leq 2 (1.1 h - 0.1)

7 (8 x + 4) = 3 (3 x + 7) + 195

x^{4} + 13 x^{2} + 36

What are the solutions to the equation x^2+7x+4=0 ?
The solutions to the equation x^2+7x+4=0 are x=(-7+sqrt(33))/2 ,x=(-7-sqrt(33))/2
Find the zeros of x^2+7x+4=0
The zeros of x^2+7x+4=0 are x=(-7+sqrt(33))/2 ,x=(-7-sqrt(33))/2