What are the solutions to the equation x(2x-7)=39 ?

The solutions to the equation x(2x-7)=39 are x= 13/2 ,x=-3

Find the zeros of x(2x-7)=39

The zeros of x(2x-7)=39 are x= 13/2 ,x=-3

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x (2 x - 7) = 39

x = \frac{13}{2}, x = - 3

Decimal Notation

x = 6.5, x = - 3

Solution steps

x (2 x - 7) = 39

Expand

x (2 x - 7) : 2 x^{2} - 7 x

2 x^{2} - 7 x = 39

Move

39

to the left side

2 x^{2} - 7 x - 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 39 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 39) = 19

x_{1, 2} = \frac{- ( - 7 ) \pm 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 19}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 19}{2 \cdot 2}

x = \frac{- ( - 7 ) + 19}{2 \cdot 2} : \frac{13}{2}

x = \frac{- ( - 7 ) - 19}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{13}{2}, x = - 3

4 w^{2} = 12 w

(210)^{2}

2 x^{2} - 4 x + 4

∣ x - 3 ∣ \leq 2

\frac{2 x - 5}{12} > - \frac{x}{4} - \frac{5}{3}

What are the solutions to the equation x(2x-7)=39 ?
The solutions to the equation x(2x-7)=39 are x= 13/2 ,x=-3
Find the zeros of x(2x-7)=39
The zeros of x(2x-7)=39 are x= 13/2 ,x=-3