What are the solutions to the equation λ^2-5λ+3=0 ?

The solutions to the equation λ^2-5λ+3=0 are λ=(5+sqrt(13))/2 ,λ=(5-sqrt(13))/2

Find the zeros of λ^2-5λ+3=0

The zeros of λ^2-5λ+3=0 are λ=(5+sqrt(13))/2 ,λ=(5-sqrt(13))/2

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λ^{2} - 5 λ + 3 = 0

λ = \frac{5 + 13}{2}, λ = \frac{5 - 13}{2}

Decimal Notation

λ = 4.30277 \dots, λ = 0.69722 \dots

Solution steps

λ^{2} - 5 λ + 3 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 3 = 13

λ_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, λ_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

λ = \frac{- ( - 5 ) + 13}{2 \cdot 1} : \frac{5 + 13}{2}

λ = \frac{- ( - 5 ) - 13}{2 \cdot 1} : \frac{5 - 13}{2}

The solutions to the quadratic equation are:

λ = \frac{5 + 13}{2}, λ = \frac{5 - 13}{2}

x^{3} + 7 x

3 (2)^{- 1}

(1 + i)^{- 20} = 0.214548

21 + 3 c = - 4 c + 28

- 30 + n = 17

What are the solutions to the equation λ^2-5λ+3=0 ?
The solutions to the equation λ^2-5λ+3=0 are λ=(5+sqrt(13))/2 ,λ=(5-sqrt(13))/2
Find the zeros of λ^2-5λ+3=0
The zeros of λ^2-5λ+3=0 are λ=(5+sqrt(13))/2 ,λ=(5-sqrt(13))/2