What is simplify-(2i)/(3+i)-(2i)/(3-i) ?

The solution to simplify-(2i)/(3+i)-(2i)/(3-i) is -6/5 i

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simplify-(2i)/(3+i)-(2i)/(3-i)

simplify

- \frac{2 i}{3 + i} - \frac{2 i}{3 - i}

- \frac{6}{5} i

Solution steps

- \frac{2 i}{3 + i} - \frac{2 i}{3 - i}

- \frac{2 i}{3 + i} = - \frac{6 i + 2}{10}

\frac{2 i}{3 - i} = \frac{6 i - 2}{10}

= - \frac{6 i + 2}{10} - \frac{6 i - 2}{10}

\frac{6 i + 2}{10} = \frac{1}{5} + \frac{3}{5} i

\frac{6 i - 2}{10} = - \frac{1}{5} + \frac{3}{5} i

= - (\frac{1}{5} + \frac{3}{5} i) - (- \frac{1}{5} + \frac{3}{5} i)

- (\frac{1}{5} + \frac{3}{5} i) = - \frac{1}{5} - \frac{3}{5} i

- (- \frac{1}{5} + \frac{3}{5} i) = - (- \frac{1}{5}) - \frac{3}{5} i

= - \frac{1}{5} - \frac{3}{5} i - (- \frac{1}{5}) - \frac{3}{5} i

Apply rule:

a - (- b) = a + b

- \frac{3}{5} i - (- \frac{1}{5}) = - \frac{3}{5} i + \frac{1}{5}

= - \frac{1}{5} - \frac{3}{5} i + \frac{1}{5} - \frac{3}{5} i

Group like terms

= - \frac{1}{5} + \frac{1}{5} - \frac{3}{5} i - \frac{3}{5} i

Add similar elements:

- \frac{1}{5} + \frac{1}{5} = 0

= - \frac{3}{5} i - \frac{3}{5} i

Add similar elements:

- \frac{3}{5} i - \frac{3}{5} i = - 2 \cdot \frac{3}{5} i

= - 2 \cdot \frac{3}{5} i

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{2 \cdot 3}{5} i

Multiply the numbers:

2 \cdot 3 = 6

= - \frac{6}{5} i

\frac{14 b + 3}{3 b} - \frac{2 b}{3 b}

z^{2} - 64

4 x - 1 + 2 x + 7 > x + 13

7 x^{2} = x^{2} + 7

x^{2} e^{x} - 3 e^{x} < 0

What is simplify-(2i)/(3+i)-(2i)/(3-i) ?
The solution to simplify-(2i)/(3+i)-(2i)/(3-i) is -6/5 i