|x-4|>7

Lösung

∣ x - 4 ∣ > 7

x < - 3 or x > 11

Intervall-Notation

(- \infty, - 3) \cup (11, \infty)

Schritte zur Lösung

∣ x - 4 ∣ > 7

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

x - 4 < - 7 or x - 4 > 7

x - 4 < - 7 or x - 4 > 7

x < - 3 or x > 11

n^{2} - 9 n + 18 = 0

4 t - 7 = 14 - 3 t

3 x + 17 = x + 3

x^{2} - 5 x + 4 > 0

x^{2} + \frac{3}{4} x + \frac{1}{8} = 0