What are the solutions to the equation 0=4x^2-4x-3 ?

The solutions to the equation 0=4x^2-4x-3 are x= 3/2 ,x=-1/2

Find the zeros of 0=4x^2-4x-3

The zeros of 0=4x^2-4x-3 are x= 3/2 ,x=-1/2

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0 = 4 x^{2} - 4 x - 3

x = \frac{3}{2}, x = - \frac{1}{2}

Decimal Notation

x = 1.5, x = - 0.5

Solution steps

0 = 4 x^{2} - 4 x - 3

Switch sides

4 x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 3) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 4}

x = \frac{- ( - 4 ) + 8}{2 \cdot 4} : \frac{3}{2}

x = \frac{- ( - 4 ) - 8}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{1}{2}

e^{2 t} \cdot e^{2 t}

\frac{6 x ^{7} y ^{5}}{4 x ^{6} y}

(x - 8)^{2} + x^{2} = (x - 8)^{2}

9 - t^{2}

3 + 22

What are the solutions to the equation 0=4x^2-4x-3 ?
The solutions to the equation 0=4x^2-4x-3 are x= 3/2 ,x=-1/2
Find the zeros of 0=4x^2-4x-3
The zeros of 0=4x^2-4x-3 are x= 3/2 ,x=-1/2