What is 1 2/3 x+(2x+1)(1/3 x-1)>= 0 ?

The solution to 1 2/3 x+(2x+1)(1/3 x-1)>= 0 is x = sqrt(3/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 2/3 x+(2x+1)(1/3 x-1)>= 0

1 \frac{2}{3} x + (2 x + 1) (\frac{1}{3} x - 1) \geq 0

x \leq - \frac{3}{2} or x \geq \frac{3}{2}

Interval Notation

(- \infty, - \frac{3}{2}] \cup [\frac{3}{2}, \infty)

Decimal Notation

x \leq - 1.22474 \dots or x \geq 1.22474 \dots

Solution steps

1 \frac{2}{3} x + (2 x + 1) (\frac{1}{3} x - 1) \geq 0

Convert mixed numbers to improper fractions:

1 \frac{2}{3} = \frac{5}{3}

\frac{5}{3} x + (2 x + 1) (\frac{1}{3} x - 1) \geq 0

Expand

\frac{5}{3} x + (2 x + 1) (\frac{1}{3} x - 1) : \frac{2 x ^{2}}{3} - 1

\frac{2 x ^{2}}{3} - 1 \geq 0

Move

1

to the right side

\frac{2 x ^{2}}{3} \geq 1

Multiply both sides by

3

2 x^{2} \geq 3

Divide both sides by

2

x^{2} \geq \frac{3}{2}

For

u^{n} \geq a

, if

n

is even then

x \leq - \frac{3}{2} or x \geq \frac{3}{2}

40 x - 120 = - 20 x + 360

f = 5 e^{0} + 2

x^{2} \cdot x^{5}

(3 x^{4})^{3}

- 4 x \geq 2

What is 1 2/3 x+(2x+1)(1/3 x-1)>= 0 ?
The solution to 1 2/3 x+(2x+1)(1/3 x-1)>= 0 is x<=-sqrt(3/2)\lor x>= sqrt(3/2)