簡約 (-j^4-4j^3-2j^2)-(-2j^4+8j^3+4j^2-8j)

解

簡約

(- j^{4} - 4 j^{3} - 2 j^{2}) - (- 2 j^{4} + 8 j^{3} + 4 j^{2} - 8 j)

j^{4} - 12 j^{3} - 6 j^{2} + 8 j

解答ステップ

(- j^{4} - 4 j^{3} - 2 j^{2}) - (- 2 j^{4} + 8 j^{3} + 4 j^{2} - 8 j)

規則を適用する:

(a) = a

(- j^{4} - 4 j^{3} - 2 j^{2}) = - j^{4} - 4 j^{3} - 2 j^{2}

= - j^{4} - 4 j^{3} - 2 j^{2} - (- 2 j^{4} + 8 j^{3} + 4 j^{2} - 8 j)

分配法則を適用する:

- (- a + b) = a - b

- (- 2 j^{4} + 8 j^{3} + 4 j^{2} - 8 j) = 2 j^{4} - 8 j^{3} - 4 j^{2} + 8 j

= - j^{4} - 4 j^{3} - 2 j^{2} + 2 j^{4} - 8 j^{3} - 4 j^{2} + 8 j

条件のようなグループ

= - j^{4} + 2 j^{4} - 4 j^{3} - 8 j^{3} - 2 j^{2} - 4 j^{2} + 8 j

類似した元を足す:

- j^{4} + 2 j^{4} = j^{4}

= j^{4} - 4 j^{3} - 8 j^{3} - 2 j^{2} - 4 j^{2} + 8 j

類似した元を足す:

- 4 j^{3} - 8 j^{3} = - 12 j^{3}

= j^{4} - 12 j^{3} - 2 j^{2} - 4 j^{2} + 8 j

類似した元を足す:

- 2 j^{2} - 4 j^{2} = - 6 j^{2}

= j^{4} - 12 j^{3} - 6 j^{2} + 8 j