What are the solutions to the equation ((-3x)/2+6)^2+x^2-2x+5=41 ?

The solutions to the equation ((-3x)/2+6)^2+x^2-2x+5=41 are x= 80/13 ,x=0

Find the zeros of ((-3x)/2+6)^2+x^2-2x+5=41

The zeros of ((-3x)/2+6)^2+x^2-2x+5=41 are x= 80/13 ,x=0

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(\frac{- 3 x}{2} + 6)^{2} + x^{2} - 2 x + 5 = 41

x = \frac{80}{13}, x = 0

Decimal Notation

x = 6.15384 \dots, x = 0

Solution steps

(\frac{- 3 x}{2} + 6)^{2} + x^{2} - 2 x + 5 = 41

Expand

(\frac{- 3 x}{2} + 6)^{2} + x^{2} - 2 x + 5 : \frac{13 x ^{2}}{4} - 20 x + 41

\frac{13 x ^{2}}{4} - 20 x + 41 = 41

Move

41

to the left side

\frac{13 x ^{2}}{4} - 20 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot \frac{13}{4} \cdot 0}{2 \cdot \frac{13}{4}}

(- 20)^{2} - 4 \cdot \frac{13}{4} \cdot 0 = 20

x_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot \frac{13}{4}}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 20}{2 \cdot \frac{13}{4}}, x_{2} = \frac{- ( - 20 ) - 20}{2 \cdot \frac{13}{4}}

x = \frac{- ( - 20 ) + 20}{2 \frac{13}{4}} : \frac{80}{13}

x = \frac{- ( - 20 ) - 20}{2 \frac{13}{4}} : 0

The solutions to the quadratic equation are:

x = \frac{80}{13}, x = 0

(37)^{2}

1 + \frac{1}{x} - \frac{2}{x + 1} < 0

6 a^{2} + 10 a - 4

(e^{4 x})^{2}

- 4 (3 - 3 n) = 3 n - 32

What are the solutions to the equation ((-3x)/2+6)^2+x^2-2x+5=41 ?
The solutions to the equation ((-3x)/2+6)^2+x^2-2x+5=41 are x= 80/13 ,x=0
Find the zeros of ((-3x)/2+6)^2+x^2-2x+5=41
The zeros of ((-3x)/2+6)^2+x^2-2x+5=41 are x= 80/13 ,x=0