36y^2-12y+1=0

解

36 y^{2} - 12 y + 1 = 0

y = \frac{1}{6}

十進法表記

y = 0.16666 \dots

解答ステップ

36 y^{2} - 12 y + 1 = 0

解くとthe二次式

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 36 \cdot 1}{2 \cdot 36}

(- 12)^{2} - 4 \cdot 36 \cdot 1 = 0

y_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 36}

y = \frac{- ( - 12 )}{2 \cdot 36}

\frac{- ( - 12 )}{2 \cdot 36} = \frac{1}{6}

y = \frac{1}{6}

二次equationの解:

y = \frac{1}{6}