What is factor 2k^2+3k-9 ?

The solution to factor 2k^2+3k-9 is (2k-3)(k+3)

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factor 2k^2+3k-9

factor

2 k^{2} + 3 k - 9

(2 k - 3) (k + 3)

Solution steps

2 k^{2} + 3 k - 9

Break the expression into groups

= (2 k^{2} - 3 k) + (6 k - 9)

Factor out

k

from

2 k^{2} - 3 k : k (2 k - 3)

Factor out

3

from

6 k - 9 : 3 (2 k - 3)

= k (2 k - 3) + 3 (2 k - 3)

Factor out common term

2 k - 3

= (2 k - 3) (k + 3)

5 w^{2} - 5 w = 0

\frac{1}{2} (- 2)

- 6 x \geq 36

\frac{a ^{2} - 81}{81 - 9 a}

- 6 x + 8 x = - 46