What are the solutions to the equation 7b^2-14b-56=0 ?

The solutions to the equation 7b^2-14b-56=0 are b=4,b=-2

Find the zeros of 7b^2-14b-56=0

The zeros of 7b^2-14b-56=0 are b=4,b=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 b^{2} - 14 b - 56 = 0

b = 4, b = - 2

Solution steps

7 b^{2} - 14 b - 56 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 7 ( - 56 )}{2 \cdot 7}

(- 14)^{2} - 4 \cdot 7 (- 56) = 42

b_{1, 2} = \frac{- ( - 14 ) \pm 42}{2 \cdot 7}

Separate the solutions

b_{1} = \frac{- ( - 14 ) + 42}{2 \cdot 7}, b_{2} = \frac{- ( - 14 ) - 42}{2 \cdot 7}

b = \frac{- ( - 14 ) + 42}{2 \cdot 7} : 4

b = \frac{- ( - 14 ) - 42}{2 \cdot 7} : - 2

The solutions to the quadratic equation are:

b = 4, b = - 2

x^{2} - 28 x = 0

25 - x^{2} \geq 0

(v^{2} + 5) (v^{2} - 3) > 9

(x + 6)^{2} = - 13

x \cdot x

What are the solutions to the equation 7b^2-14b-56=0 ?
The solutions to the equation 7b^2-14b-56=0 are b=4,b=-2
Find the zeros of 7b^2-14b-56=0
The zeros of 7b^2-14b-56=0 are b=4,b=-2