What are the solutions to the equation k^2-9=0 ?

The solutions to the equation k^2-9=0 are k=3,k=-3

Find the zeros of k^2-9=0

The zeros of k^2-9=0 are k=3,k=-3

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k^{2} - 9 = 0

k = 3, k = - 3

Solution steps

k^{2} - 9 = 0

Move

9

to the right side

k^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 9, k = - 9

9 = 3

- 9 = - 3

k = 3, k = - 3

3 (x - 4) = - 18

\frac{- 12}{- 2} \leq \frac{- 2 x}{- 2} \leq \frac{6}{- 2}

lo g_{0.001} (10) = y

\frac{12}{25}

x^{2} - 24 x + 62 = - 9 x + 6

What are the solutions to the equation k^2-9=0 ?
The solutions to the equation k^2-9=0 are k=3,k=-3
Find the zeros of k^2-9=0
The zeros of k^2-9=0 are k=3,k=-3