What are the solutions to the equation (x+8)^2=2x+15 ?

The solutions to the equation (x+8)^2=2x+15 are x=-7

Find the zeros of (x+8)^2=2x+15

The zeros of (x+8)^2=2x+15 are x=-7

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(x + 8)^{2} = 2 x + 15

x = - 7

Solution steps

(x + 8)^{2} = 2 x + 15

Expand

(x + 8)^{2} : x^{2} + 16 x + 64

x^{2} + 16 x + 64 = 2 x + 15

Move

15

to the left side

x^{2} + 16 x + 49 = 2 x

Move

2 x

to the left side

x^{2} + 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- 14 \pm 0}{2 \cdot 1}

x = \frac{- 14}{2 \cdot 1}

\frac{- 14}{2 \cdot 1} = - 7

x = - 7

The solution to the quadratic equation is:

x = - 7

∣ 2 - y ∣ = y - 2

10000

(\frac{1}{4} x^{2} - \frac{1}{6} y^{2})^{2}

8 x + 15 = - 2 x + 25

8 \cdot (\frac{1}{2})

What are the solutions to the equation (x+8)^2=2x+15 ?
The solutions to the equation (x+8)^2=2x+15 are x=-7
Find the zeros of (x+8)^2=2x+15
The zeros of (x+8)^2=2x+15 are x=-7