What are the solutions to the equation (2w+11)w=63 ?

The solutions to the equation (2w+11)w=63 are w= 7/2 ,w=-9

Find the zeros of (2w+11)w=63

The zeros of (2w+11)w=63 are w= 7/2 ,w=-9

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(2 w + 11) w = 63

w = \frac{7}{2}, w = - 9

Decimal Notation

w = 3.5, w = - 9

Solution steps

(2 w + 11) w = 63

Expand

(2 w + 11) w : 2 w^{2} + 11 w

2 w^{2} + 11 w = 63

Move

63

to the left side

2 w^{2} + 11 w - 63 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 63 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 63) = 25

w_{1, 2} = \frac{- 11 \pm 25}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 11 + 25}{2 \cdot 2}, w_{2} = \frac{- 11 - 25}{2 \cdot 2}

w = \frac{- 11 + 25}{2 \cdot 2} : \frac{7}{2}

w = \frac{- 11 - 25}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

w = \frac{7}{2}, w = - 9

\frac{6}{4} = \frac{x}{6}

x^{5} - y^{5}

- 36 + 36

\frac{12 x ^{5} y ^{7}}{4 x ^{6} y ^{3}}

2 x + 20 = 4 x - 6

What are the solutions to the equation (2w+11)w=63 ?
The solutions to the equation (2w+11)w=63 are w= 7/2 ,w=-9
Find the zeros of (2w+11)w=63
The zeros of (2w+11)w=63 are w= 7/2 ,w=-9